1 条题解
-
0
思路
很简单,就是前缀和,但是计算区间时需要使用
sum[r-1]-sum[l-1],还需要避免越界加密代码
偏移量:
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#define lS56LGeDwmym6 cin #define iLBqG6NtLs_Vl cout #define D0hhMctG else #define LBd8cJQHMs endl #define zlG6RRlfONL false #define GFoslWcgz for #define oojrnaOuxPo2g i #define _kWHsLNaU51KzqhxPEl if #define No0FUwxbphGyAsZbr int #define _Iww0JUkTbb2WgcN0X ios #define JLu2sIZjn1Lu_BpEcg l #define ITBP51Ym3goHD ll #define WaFM5GcW1 long #define oYs3swZzcsYjfOG_ lsum #define x9KTUcM7 m #define xvnNFGowfDyYqRPOck main #define vhhXFe50U n #define IaZKsqkx_9IEFh namespace #define u1Qtyrwh r #define oJ7gvX0xu6tR8Bn return #define GvjRegng rsum #define jY3QNayW9CESv1c3M s #define JEXvB2QyE std #define XFk92444AAbAG string #define BXcp0JyGlc5YEoWvsGa sum #define sDPRvcO8UVZjBG7 sync_with_stdio #define r0HqBqatmaNAG tie #define TLgI9zrpsZ using #define zv4eNPBsNoxLYQ06X vector #include<bits/stdc++.h> #define ll long long TLgI9zrpsZ IaZKsqkx_9IEFh JEXvB2QyE; No0FUwxbphGyAsZbr xvnNFGowfDyYqRPOck() { _Iww0JUkTbb2WgcN0X::sDPRvcO8UVZjBG7(zlG6RRlfONL); lS56LGeDwmym6.r0HqBqatmaNAG(0); iLBqG6NtLs_Vl.r0HqBqatmaNAG(0); ITBP51Ym3goHD vhhXFe50U,x9KTUcM7; lS56LGeDwmym6>>vhhXFe50U>>x9KTUcM7; XFk92444AAbAG jY3QNayW9CESv1c3M; lS56LGeDwmym6>>jY3QNayW9CESv1c3M; zv4eNPBsNoxLYQ06X<ITBP51Ym3goHD> BXcp0JyGlc5YEoWvsGa(vhhXFe50U+5,0); GFoslWcgz(ITBP51Ym3goHD oojrnaOuxPo2g=0;oojrnaOuxPo2g<vhhXFe50U-1;oojrnaOuxPo2g++) { _kWHsLNaU51KzqhxPEl(oojrnaOuxPo2g==0) BXcp0JyGlc5YEoWvsGa[oojrnaOuxPo2g]=(jY3QNayW9CESv1c3M[oojrnaOuxPo2g]==jY3QNayW9CESv1c3M[oojrnaOuxPo2g+1]); D0hhMctG BXcp0JyGlc5YEoWvsGa[oojrnaOuxPo2g]=BXcp0JyGlc5YEoWvsGa[oojrnaOuxPo2g-1]+(jY3QNayW9CESv1c3M[oojrnaOuxPo2g]==jY3QNayW9CESv1c3M[oojrnaOuxPo2g+1]); } GFoslWcgz(ITBP51Ym3goHD oojrnaOuxPo2g=1;oojrnaOuxPo2g<=x9KTUcM7;oojrnaOuxPo2g++) { ITBP51Ym3goHD JLu2sIZjn1Lu_BpEcg,u1Qtyrwh,oYs3swZzcsYjfOG_,GvjRegng; lS56LGeDwmym6>>JLu2sIZjn1Lu_BpEcg>>u1Qtyrwh; _kWHsLNaU51KzqhxPEl(u1Qtyrwh-2<0) GvjRegng=0; D0hhMctG GvjRegng=BXcp0JyGlc5YEoWvsGa[u1Qtyrwh-2]; _kWHsLNaU51KzqhxPEl(JLu2sIZjn1Lu_BpEcg-2<0) oYs3swZzcsYjfOG_=0; D0hhMctG oYs3swZzcsYjfOG_=BXcp0JyGlc5YEoWvsGa[JLu2sIZjn1Lu_BpEcg-2]; iLBqG6NtLs_Vl<<GvjRegng-oYs3swZzcsYjfOG_<<LBd8cJQHMs; } oJ7gvX0xu6tR8Bn 139; }
- 1
信息
- ID
- 103
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 3
- 标签
- 递交数
- 48
- 已通过
- 13
- 上传者